sjedufei 2013-08-02 17:32:17 4167次浏览 0条回复 0 0 0
select  * from manhua left join [b](select id as qid,manhuaid,addtime as qaddtime from quick_promoted where typeid=0) [/b]as quick_type on manhua.id=quick_type.manhuaid 

$criteria->join = "left JOIN quick_promoted on t.id=quick_promoted.manhuaid ";

请问 yii 如何 将加粗部分 加入 进来 做连接查询

    没有找到数据。
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